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Hooke's law if a 3 kg mass stretches a spring 40 cm how far will a 5 kg mass stretch the spring?
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass: F=kx F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2) (3 kg)(9.8 m/s2)=(.40 m)k k=[(3 kg)(9.8 m/s2)/(.40 m)] Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass: F=kx F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2) (5 kg)(9.8 m/s2)=kx (5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x x=2/3 m The 5 kg mass would stretch the spring two thirds of a meter.
Can you measure mass using spring balance?
Yes
How do you measure the mass of a cow?
Put her on a truck and have the truck weighed on a balance scale (NOT a spring scale). From this you can get true mass.
What unit of measure is spring scale to?
Mass (Newtons(N)) and Weight (grams(g))
Can the speed and frequency of the waves in a spring be changed?
All violinists believe so. The springs (= violin string) properties of frequency and timbre can be altered by the pressure of the bow against the string. Even in a simple coiled spring, you'll find the period of the pluck waves will change as the spring is elongated. But the purist will point out (correctly) that it is now a different spring. My favourite demonstration is of a rubber band about 200 mm long, with a mass at the lower end. This spring+mass apparatus has at least three resonant periods! First is that of a simple pendulum. Second is that of a torsional resonance (much slower). Third is that of the vertical oscillation of a spring-mass system.
What mass would be needed to stretch the spring to a length of 60 cm?
1,500 grams2,500 grams500 grams2,000 grams
A mass of 1.7kg caused a vertical spring to scretch 6m what's the spring constant?
A mass of 1.7kg caused a vertical spring to stretch 6m so the spring constant is 2.78.
A mass of 4 kg stretches a spring 6 cm what is the mass of an object which streches the spring 9 cm?
Using Hooke's Law, we can set up a proportion to solve for the mass of the object stretching the spring 9 cm. Since the force required to stretch a spring is directly proportional to the distance stretched, an object with a mass of 6 kg would stretch it to 9 cm.
Predict how many centimeters the spring will stretch if a total mass of 700 grams were attached?
To predict how many centimeters the spring will stretch, we need to know the spring constant in N/cm and apply Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to its extension. By knowing the spring constant and the total mass attached, we can calculate the stretch.
Suggest suitable Experiments to find spring constant of a helical spring?
Connect a mass to the bottom of the spring. (depending on the spring size, the mass will vary, the larger the spring the greater the mass u can use) Suppose you use a 100 g mass on a spring, measure the amount by which it stretches and record the data. Use hooke law to figure out the constant of the spring. K = m.g/x m = mass, g =gravity, x = stretch
What do a pan-balance and the spring scale each measure?
A pan balance measures mass by comparing an unknown mass to a known mass using weights on a balancing scale. A spring scale measures force by the amount of stretch or compression in a spring when a force is applied to it.
How much will the spring be stretched 25kg of 4500Nm?
To calculate the spring stretch, you need to use Hooke's Law formula which states F = kx, where F is force, k is the spring constant, and x is the displacement/stretch of the spring. Rearranging the formula to solve for x, you get x = F/k. Given force (4500 N) and mass (25 kg), you can calculate the force as F = m*g, where m is the mass and g is the acceleration due to gravity (9.81 m/s^2). Then, you can calculate the spring constant using Hooke's Law formula with the given force and stretch. Subsequently, use this spring constant to determine the stretch of the spring by rearranging the Hooke's Law formula.
How would k vary with different mass of trapped gas?
The value of the spring constant ''k'' in a spring-mass system would remain constant regardless of the mass of the trapped gas, as it only depends on the stiffness of the spring and not on the mass attached to it.
What is the effective mass of spring?
The effective mass of a spring is the mass that would behave the same way as the spring when subjected to a force or acceleration. It is a concept used in physics to simplify calculations in systems involving springs. The effective mass of a spring depends on its stiffness and the mass it is attached to.
What happens to the length of a spring when you add a mass to it?
The length of the spring increases when you add a mass to it due to the force of gravity pulling the mass downwards and stretching the spring. This change in length is proportional to the weight of the added mass and the spring's stiffness.
What is the difference between triple beam balance and a spring scale?
A triple beam balance measures mass by comparing the unknown mass to a set of standard masses on three beams with riders. A spring scale measures weight by the amount of stretch in a spring when an object is hung from it. Triple beam balances are more accurate for measuring mass, while spring scales are better for measuring weight.
If a 40kg weight is hanging on a spring with spring constant 50Nm how far will the spring stretch?
The net force acting in the stretch direction on the spring is proportional to its deformation (e.g., its stretch). In math talk that's F = kdX where k = 50 N/m and F = mg = 40*9.81 is the weight of the m mass. NOTE: 40 kg is not...not...a weight, it's a measure of mass. To get the weight, the force of gravity, we must multiply by g = 9.81 m/sec^2 which is a typical average acceleration due to gravity on the Earth's surface. So the stretch dX = F/k = mg/k = 40*9.81/50 = 7.848 meters. ANS.
