An integer is odd if and only if it is not divisible by two.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
true
The true biconditional statement that can be formed is: "A number is even if and only if it is divisible by 2." This statement combines both the original conditional ("If a number is divisible by 2, then it is even") and its converse ("If a number is even, then it is divisible by 2"), establishing that the two conditions are equivalent.
Yes, it is true that if a number is divisible by 4, then it is even. A valid biconditional statement would be: "A number is divisible by 4 if and only if it is even." This means that not only does divisibility by 4 imply that the number is even, but also that every even number that is divisible by 4 will satisfy this condition.
In mathematical logic, An integer A if divisible by 100 iff the last two digits are 0. "iff" stands for "if and only if".
The definition of divisible is "found everywhere".
2
Prime numbers are by definition only divisible by 1 and itself.
One number is divisible by another number if that division results in an integer.
By definition, prime numbers can only be divisible by one and themselves, so no.
That is because, by definition, an even number is one that is divisible by 2.
It is a multiple of 6. There are an nfinite number of them and so cannot be listed. Each of these will be divisible by 6 (by definition). They will also be divisible by 2 and 3.