one
x=4y+1 x=4y-1 No,they have different solutions.
It works out that the solutions are: x = 3 and y = 2
Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5
Each of these have an infinite number of solutions. Never can they be equal.
Do you want the solutions to the equations? If so then: x = 7 and y = 4
No.
The equation has infinitely many solutions.
To determine the number of solutions for the system of equations (x + 2y = 10) and (4y - 20 = 2x), we can rewrite the second equation as (2x - 4y + 20 = 0). Rearranging gives us (x = 2y + 10). Substituting this into the first equation leads to a consistent system, indicating that there is exactly one solution where the lines intersect. Thus, the system has one unique solution.
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
No.
x = 4y 3x - 2y = 20 Substituting the value of x into the second equation, 3*(4y) - 2y = 20 ie 12y - 2y = 20 or 10y = 20 so that y = 2 Then x = 4y = 4*2 = 8. So (x , y) = (8 , 2)
Straight line equations:- And if: 3x-4y = 8 Then: y = 0.75x-2 whereas 0.75 or 3/4 is the slope and -2 is the y intercept