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9x equals 53 - 4y 3y equals 26 - 4x?
(5, 2)
3x-3y equals 12 4y-8x equals -16?
(0,-4)
How do you solve y2 - 3y plus 2 plus 3y - 4y - 5?
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
What is the answer to 6x plus 4y equals 62 and 5x plus 3y equals 51?
(9,2)
If y plus 3y plus 10 equals 70 what does y equal?
If y + 3y + 10 = 70, then 4y + 10 = 70, and 4y = 60. We then find that y = 60/4 = 15.
What is the answer 5x - 3y equals 23 7x - 4y equals 33?
5x - 3y = 23 7x - 4y = 33 multiply 1st eq by 4 and second by 3: 20x - 12y = 92 21x -12y = 99 Now subtract equations: -x = -7 x = 7 substitute x into either equation: 5(7) - 3y = 23 35 - 3y = 23 -3y = -12 y = 4
5x-3y equals 23 7x-4y equals 33?
5x -3y = 23 7x - 4y = 33 This is simultanreous equations. Arbitrarily decide which letter to eliminate. In this case 'y' To do this multiply the top eq'n by '-4' and the bottom by '3' Hence -20x + 12y = -92 21x - 12y = 99 Add the two eq'ns. This will eliminate 'y' x = 7 Substitute into either eq'n for 'y' 49 - 4y = 33 -4y = - 16 y = 4 Hence (x,y) = ( 7,4)
4y plus 4 equals 3y-5?
4y + 4 = 3y - 5 y = -9
2x plus 3y equals 17and3x plus 4y equals 24then5x plus 7y equals?
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
What is the x value 2x-3y equals -15 x equals 4y?
If: 2x-3y = -15 and x = 4y Then: x = -12 and y = -3
What is y if 4-3y-y equals 0?
4 - 3y - y = 04 - 4y = 0add 4y to both sides4 = 4ydivide both sides by 4y = 1
What is 4y-3y?
4y-3y = 1
9x equals 53 - 4y 3y equals 26 - 4x?
(5, 2)
3x-3y equals 12 4y-8x equals -16?
(0,-4)
How do you simplify 4y plus 23 - y - 6?
Add like terms: (4y - y) + (23 - 6) = 3y + 17
How do you solve the system equation 4x plus 3y equals 33 and x equals -4y-25?
So 1. 4x + 3y = 33 2. x = -4y - 25 Two linear equations (degree one polynomial) are likely to be consistent. If you have some knowledge with matrices, using Gaussian Elimination it can be done easily. I will assume that knowledge is not available. It is known that x and y are related in a way such that both equations are satisfied, in particular x = -4y - 25. so 4x is namely 4(-4y - 25) and 4x + 3y = 4(-4y - 25) + 3y which is 33. Simplify the single variable polynomial y and solve for y. It should be an easy way of rearranging things. For the matrix method, post in discussion.
How do you solve y2 - 3y plus 2 plus 3y - 4y - 5?
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
