3_2
1/5 2/3
The sum of 23 and 46 is 69.
Here's one way to work that out. Let's call the numbers "a" and "b" We're told: a + b = 23 ab = 108 We can take one of those two, solve it for either a or b, substitute it into the other, and solve for the other variable using our new equation: a + b = 23 b = 23 - a ∴ a(23 - a) = 108 -a2 + 23a = 108 a2 - 23a + 108 = 0 a2 - 23a + (23/2)2 = (23/2)2 - 108 (a - 23/2)2 = 529/4 - 432/4 (a - 23/2)2 = 97/4 a - 23/2 = ± √(97/4) a = (23 ± √97) / 2 So the two numbers that meet this condition are (23 - √97) / 2 and (23 + √97) / 2
121
121/2 = 60.5
-2/15 or pronounced negative two fifteenths
8x-1=23-4x 12x=24 x=2
1, 2, 11, 22, 23, 46, 121, 242, 253, 506, 2783, 5566
60.5
Ans - 2+121=123
To find the radius of a circle with an area of 121 square units, you first need to use the formula for the area of a circle, which is A = πr^2, where A is the area and r is the radius. In this case, the area is 121, so 121 = πr^2. To solve for the radius, you divide both sides by π and then take the square root, giving you r = √(121/π) ≈ 6.18 units.
121 = (11)2