0
3_2
What else can I help you with?
Which strategy would be used to solve 15 23?
1/5 2/3
Solve 23 46?
The sum of 23 and 46 is 69.
What two numbers would have a product of 108 and a sum of 23 at the same time?
Here's one way to work that out. Let's call the numbers "a" and "b" We're told: a + b = 23 ab = 108 We can take one of those two, solve it for either a or b, substitute it into the other, and solve for the other variable using our new equation: a + b = 23 b = 23 - a ∴ a(23 - a) = 108 -a2 + 23a = 108 a2 - 23a + 108 = 0 a2 - 23a + (23/2)2 = (23/2)2 - 108 (a - 23/2)2 = 529/4 - 432/4 (a - 23/2)2 = 97/4 a - 23/2 = ± √(97/4) a = (23 ± √97) / 2 So the two numbers that meet this condition are (23 - √97) / 2 and (23 + √97) / 2
What is 242 divided by 2?
121
What is the quotient of 121 and 2?
121/2 = 60.5
Solve 8x-1 equals 23-4x?
8x-1=23-4x 12x=24 x=2
Solve for 4x 3 -3x-2?
-2/15 or pronounced negative two fifteenths
What is the factor of 5566?
1, 2, 11, 22, 23, 46, 121, 242, 253, 506, 2783, 5566
What is the exponent for 121?
The number 121 can be expressed as a power of 11. Specifically, ( 121 = 11^2 ). Therefore, the exponent for 121 is 2.
What is 121 divided by 2?
60.5
What is 2 plus 121?
Ans - 2+121=123
What is the radius of a circle With an area of 121 squared?
To find the radius of a circle with an area of 121 square units, you first need to use the formula for the area of a circle, which is A = πr^2, where A is the area and r is the radius. In this case, the area is 121, so 121 = πr^2. To solve for the radius, you divide both sides by π and then take the square root, giving you r = √(121/π) ≈ 6.18 units.
