If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
x3 + 3x2 - 4x -12 x2(x + 3) - 4(x + 3) (x2 - 4)(x+3)
(3x - 5)(x + 3)
3x2 + 4x + 1 = ?? This is a quadratic equation. The equation can be made to equal any number and this will determine the corresponding values of x. EXAMPLE : 3x2 + 4x + 1 = 96 (x = 5 or x = -19/3) Alternatively, if x is known then this will determine the result. EXAMPLE : If x = 2 then (3 x 4) + (4 x 2) + 1 = 12 + 8 + 1 = 21 In normal use, a quadratic equation is presented as equal to zero. In this example : 3x2 + 4x + 1 = 0
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
The answer is 3! Let x represent the number. From the problem: 3x2-4x=15 Solve for x: 3x2-4x=15 3x2-4x-15=0 (3x+5)(x-3)=0 x=-5/3 OR x=3 However, we were asked for a whole number. -5/3 is not a whole number. So x=3 is the only whole number solution.
3x2-4x-4=0 (3x+2)(x-2)+0 x=-3/2, 2
x3 + 3x2 - 4x -12 x2(x + 3) - 4(x + 3) (x2 - 4)(x+3)
two complex
8(4x+ 3)
(3x - 5)(x + 3)
no 3x2=6 then 4x-15= -60 so 6 added with - 60 = -54
It is: x = 5/3 and x = -3
They are: x = 5/3 and x = -3
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.