Assuming that you can only use each number once, then one solution is :-
6 x (22 - 2 - 39/3) = 6 x (20 - 13) = 6 x 7 = 42
22 + 22 - 2 = 42
The GCF is 2.
39: 1, 3, 13, 39 40: 1, 2, 4, 5, 8, 10, 20, 40 42: 1, 2, 3, 6, 7, 14, 21, 42 43: 1, 43 44: 1, 2, 4, 11, 22, 44 45: 1, 3, 5, 9, 15, 45
44 = 22 x 11 63 = 32 x 7
One solution is, 31 + (2 x 4) = 31 + 8 = 39 Another is, 42 - (1 x 3) = 42 - 3 = 39
The common factors of 22 and 42 are: 1 and 2
We can get 29 by using their squares like: (42 + 32 + 22) / 1 = 29
These are always difficult for me; I always end up using trial and error. In this particular case, here is a way to get 39 out 1, 2, 3 and 4: 42 - 31 If you are not allowed to use exponents, then there is: 31 + 4 * 2
-1 * 42 = -42 1 * -42 = -42 -2 * 22 = -42 2 * -22 = -42 -3 * 14 = -42 3 * -14 = -42 There are many ways to multiply two numbers to equal -42. However, one must be negative.
Half way between 36 and 42 is (36 + 42) ÷ 2 = 39.
1, 2, 11, 22 1, 2, 3, 6, 7, 14, 21, 42
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42