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Q: How Many odd Three Digit Numbers Can Be Formed From 0 1 2 3 4 5 6?

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Related questions

512

There are 900 of them.

27 three digit numbers from the digits 3, 5, 7 including repetitions.

48 of them if digits may not be repeated. 100 if they can.

9999

100,000

Any 3 out of 4 = 4. Each set can be arranged 6 ways so 24 different numbers.

12

There are 450 such numbers.

21

There are 900 three-digit numbers, ranging from 100 to 999.

A lot

There are 504 such numbers.

24

6

840

823543

There are 60480 numbers.

81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.

There are only 999 three digit whole numbers.

There are 90 palindromic numbers.

There are 3024 of them.

180 of them.

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

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