2z-28 = -26
(2+x+y+6+z) += 9x,y and z are variables, there are 3.
3xz
-2z + 3
2z+17=21 subtract 17 from both sides. 2z=4 divide both sides by 2 z=2
2z-28 = -26
There are infinitely many solutions. One linear equation in two variables cannot be solved to give a single answer.
The sum of the given expression would depend on the values of the variables which have not been given.
2z(5z - 1)(25z^2 + 5z + 1)
9x + 2y = -11 I'm sorry to say this, but it is absolutely "impossible" to figure variables out with only one equality. You need one more of that to get those two variables (if you have only one variable it is perfectly fine and you can do it)
(2+x+y+6+z) += 9x,y and z are variables, there are 3.
(-3) x (-2z - 7) = 6z + 21 = 3 (2z + 7)
3xz
-2z + 3
16(2z-3)
You cannot solve this statment as there is nothing to equate to it. However, it will factor. 9 - 4z^2 First we note that both '9' and '4' are squared numbers. 9 = 3^(2) & 4 = 2^(2) So we can re-write the statement as 3^(2) - (2z)^(2) Note that it now has two squared terms with a negative between them . This will factor to 3^(2) = (2z)^2 = ( 3 - 2z_)(3 + 2z) NOTE the different signs. NB Two squared terms with a positive(+) between them will NOT factor.
To solve for two unknown variables (x and y) you require two independent equations,