(1) y2-2zy-2y-2z-3 = y2 -2y (z+1) - (2z+3)
Delta = [-(z+1)]2 - (- (2z+3)) = z2+2z+1+2z+3= z2+2z+4 = (z+2)2
(If used the reduced form as b=-2(z+1) is even, b'=-(z+1) and delta=b'2-ac)
y=(z+1) ± (z+2) so y = 2z+3 or y =-1
So the (1) can be written (y-2z-3)(y+1)
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If that is + 192 then divide all terms by 3 and it is (x+8)(x+8) when factored
Math books and teachers will make it look like all trinomials can be factored, but many are not.
Basically, service loads are those applied loads which have not yet been factored. Also known as "working loads"
X(5-8)
8(7c - 5d)