Subtract first from second gives -4x = 16 so x = -4 and y = -7
6x+11=92-3x +3x +3x 9x+11=92 -11 -11 9x=81 divide by 9 x=9
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
9x+27 = -81 9x = -81-27 9x = -108 x = -12
Multiply the first equation by 3 to give 9x + 15y = 21
2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2
Subtract first from second gives -4x = 16 so x = -4 and y = -7
-9x + 2y = -69 So 2y = 9x - 69 The other equation can be written as 6x - 4y = 54 or 6x - 2*2y = 54 Substituting for 2y gives 6x - 2*(9x - 69) = 54 6x - 18x + 138 = 54 12x = 84 x = 7 and then 2y = 9x - 69 = 9*7 - 69 = 63-69 = -6 so that y = -3
9x + 3x - 9x = 6 + 8x - 113x = 8x - 11-5x = -11x = 2.2 or 11/5
9x + 2y = 5 y - 2x + 3 = 0 Put both equations into the same format. It is often easiest to have just one unknown on (say) the left-hand side of the equation. Let's pick y for this purpose. 2y = -9x + 5 y = 2x - 3 Now make the coeficients of y the same. This can be done by multiplying the 2nd equation by 2. 2y = -9x + 5 2y = 4x - 6 Then, -9x + 5 = 4x - 6 13x = 11 : x = 11/13 And substitue for x in any equation - take the very first original equation. 9x + 2y = 5 99/13 + 2y = 5 : 2y = 5 - 78/13 = - 28/13 y = - 14/13
6x + 47 = 9x + 11 6x + 36 = 9x 36 = 3x 12 = x
- x - 2y + 9x - y + 3x = 0 1.) Add like - terms 11x - 3y = 0 x = - 3/11y y = 11/3y
If: 9x-2y = 14 Then: y = 4.5x-7 in slope intercept form
9x-11 = 6x+1 9x-6x = 1+11 3x = 12 x = 4
X= -2
(7x-3y) + (2x+5y) = 9x+2y
5x + 51 = 9x + 11 Becomes 40 = 4x So x = 10