It works out as: 9 -6 +5 = 8
There are infinitely many sets that will satisfy the requirements. Three examples are: {0, 6, 8, 8, 8} {2, 6, 6, 6, 10} {√3, 5, 5, 12-2*√3, √3+8}
There are no three consecutive numbers that add up to twenty.Proof:5+6+7=186+7+8=217+8+9 = 24
Four numbers 6, 8, 9, 10
5 and 8-5 and -8
3 and 5, 4 and 6, 8 and 12
4, 5, 6, 7, 8.
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
three and five or six and two5,3 4,46,2(1+2) = 3 + 5 = 8(2+3) = 5 +4 = 9 - 1 = 8(3+4) = 7 + 1 = 8(4+5) = 9 - 1 = 8(5+6) = 11 - (1+2) = 11 - 3 = 8(6*4) - (3*5) = 24 - 15 = 9 - 1 = 8Using all the numbers 1 through 6(1*2) = 2 + 3 + 4 + 5 - 6 = 8
what is the median of these numbers 5 6 6 7 8 9 9 0 2 3 5 6 8 8 8 8 0 1 2 3 5 5 6 7 7 8 0 2 4 5 7 8
(2 - 5 + 6)*8 = 3*8 = 24
6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.
The common denominator for the fractions 6, 5, and 8 is the least common multiple (LCM) of these numbers. The LCM of 6, 5, and 8 is 120. Therefore, 120 is the common denominator for these numbers.