4, 5, 5, 8, 8
3, 4, 5, 6, 7, 8, and 9.
(3, 4, 6, 8, 9)
4 4 6 6 10
3 (15/5), 21/5, 27/5, 33/5, 39/5, 9(45/5) Range = 9 - 3 = 6 Mean = (15/5 + 21/5 + 27/5 + 33/5 + 39/5 + 45/5)/6 = (180/5)/6 = 36/6 = 6
3,5,6,7,9
4, 5, 5, 8, 8
3, 4, 5, 6, 7, 8, and 9.
(3, 4, 6, 8, 9)
4 4 6 6 10
3 (15/5), 21/5, 27/5, 33/5, 39/5, 9(45/5) Range = 9 - 3 = 6 Mean = (15/5 + 21/5 + 27/5 + 33/5 + 39/5 + 45/5)/6 = (180/5)/6 = 36/6 = 6
(3, 4, 5, 7, 8, 9)
(1, 3, 3, 3, 5, 5, 6, 6, 8, 10)
1, 5, 5, and 5 5+5+5+1=16/4=4 5-1=4
It is easy to prove that such a set of numbers cannot exist. If the median is -1 and the mean is different from the median, then there must be at least one number that is less than or equal to -1. Then, if the range is 6, the largest number can only be 5. If the largest number is 5 and the mean is 5, then all the numbers must be 5. That is not possible because there is at least one that is -1 or smaller.
5, 6, 9, 10, & 10
3, 3, 5, 9, 10