They cant because they are different shapes... Trust me I'm doing this right now in my class we r talking about area and perimeter. Our book right now we r on like our 4th or 5th math book already and its called Covering and Surrounding Two-Dimensional Measurement.. so ya i hope that was helpful if not I'm so sorry..:(
Not so fast! Perimeter is simply distance that bounds an area. Suppose you have six sided shape hexagon; say each side is 6 inches and perimeter is thus 6 x 6 = 36. Now suppose you have a square 9 inches on a side and thus perimeter is 9 x 4 = 36. Both are different shapes with same perimeter.
Yard is a measure of length; there is no standard conversion to area. Different figures of the same length, or of the same perimeter, can have different areas.
If you mean the perimeter or circumference, it depends: different figures may have different perimeters or circumferences, even if they have the same area.
There is no name for such shapes because "same size" is not defined. Does it mean same area? same perimeter? same major diagonal?
You can't. There are an infinite number of different figures that all have the same base but different heights.
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
The perimeter will scale by the same factor.
They may be of different sizes. Congruent figures have the same size.They may be of different sizes. Congruent figures have the same size.They may be of different sizes. Congruent figures have the same size.They may be of different sizes. Congruent figures have the same size.
It's very easy for two rectangles to have the same area and different perimeters,or the same perimeter and different areas. In either case, it would be obvious toyou when you see them that there's something different about them, and theywould not fit one on top of the other.But if two rectangles have the same area and the same perimeter, then to look at themyou'd swear that they're the same rectangle, and one could be laid down on the otherand fit exactly.
I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).
You can't. Different shapes with the same perimeter may have different areas.
not necessarily. take the example of a 3x3 square and a 4x2 rectangle. Both have a perimeter of 12. but the square has an area of 9 and the rectangle has an area of 8.
Yes, two figures can have the same perimeter and different areas. For example, take a square with a perimeter of 16 units. This means that each side is 4 units, and its area is 16 units squared. Now, take a rectangle with width of 7 units and length of 1 unit. The perimeter of this figure is still 16 units ( (7 x 2) + (1 X 2) ), but its area is 7 units ( 7 x 1 ). This is only a basic example of the application of this problem.