11+12+13=36
The numbers are 36, 37 and 38.
They are 11, 12 and 13.
34, 35 and 36.
11, 12 and 13
36
Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.
6 + 8 + 10 + 12 = 36 10 + 12 + 14 = 36
To find three consecutive numbers that add up to 108, let the numbers be represented as ( x - 1 ), ( x ), and ( x + 1 ). The equation is ( (x - 1) + x + (x + 1) = 108 ). Simplifying this gives ( 3x = 108 ), leading to ( x = 36 ). Therefore, the three consecutive numbers are 35, 36, and 37.
No, they are consecutive but sum means that if you add them together it will equal 36. Also 2 is not odd. The numbers you are looking for are 17 and 19.
114
The two square numbers that add together to make 100 are 36 and 64. Specifically, (6^2 = 36) and (8^2 = 64). When you add them together, (36 + 64 = 100).
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36