They are 11, 12 and 13.
The consecutive numbers that add up to 36 are 11, 12, and 13. When you add these three numbers together (11 + 12 + 13), the sum is 36.
The numbers are 36, 37 and 38.
34, 35 and 36.
To find three consecutive numbers that add up to 108, let the numbers be represented as ( x - 1 ), ( x ), and ( x + 1 ). The equation is ( (x - 1) + x + (x + 1) = 108 ). Simplifying this gives ( 3x = 108 ), leading to ( x = 36 ). Therefore, the three consecutive numbers are 35, 36, and 37.
11, 12, and 13
The consecutive numbers that add up to 36 are 11, 12, and 13. When you add these three numbers together (11 + 12 + 13), the sum is 36.
The numbers are 36, 37 and 38.
34, 35 and 36.
To find three consecutive numbers that add up to 108, let the numbers be represented as ( x - 1 ), ( x ), and ( x + 1 ). The equation is ( (x - 1) + x + (x + 1) = 108 ). Simplifying this gives ( 3x = 108 ), leading to ( x = 36 ). Therefore, the three consecutive numbers are 35, 36, and 37.
11, 12, and 13
11+12+13=36
The numbers are 11, 12 and 13.
The numbers are 11, 12 and 13.
11, 12 and 13
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
The numbers are 36, 37 and 38.
35+36+37