Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.
The numbers are 36, 37 and 38.
They are 11, 12 and 13.
34, 35 and 36.
6 + 8 + 10 + 12 = 36 10 + 12 + 14 = 36
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
11+12+13=36
The numbers are 36, 37 and 38.
11, 12 and 13
They are 11, 12 and 13.
34, 35 and 36.
36
6 + 8 + 10 + 12 = 36 10 + 12 + 14 = 36
No, they are consecutive but sum means that if you add them together it will equal 36. Also 2 is not odd. The numbers you are looking for are 17 and 19.
114
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
The numbers are 11, 12 and 13.
The numbers are 11, 12 and 13.