Since there are no absolute values in the expression, it would appear that the task has already been accomplished!
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
Yes, you can apply the distributive property in expressions involving absolute values, but it's important to consider the properties of absolute values. The distributive property states that ( a(b + c) = ab + ac ), and this can be used with absolute values, such as ( |a(b + c)| = |ab + ac| ). However, the absolute value of a sum is not necessarily equal to the sum of the absolute values, meaning ( |a + b| \neq |a| + |b| ) in general. Thus, careful attention is needed when manipulating expressions involving absolute values.
The square root of Ab^2 is |b|√A, where A is a positive real number and b is any real number. The absolute value of b is taken to ensure the result is always positive or zero. If b is negative, the result will be |b| times the square root of A.
15
|a + b| ≤ |a| + |b|
the absolute value of a over b is not the invers. it is a posative number of a over b. when you see the absolute value, just change it to a posative number. if it is posative, you have your answer.
generally we calculate voltage difference not absolute voltage but we say it voltage so if V(AB) is positive then V(BA) will be negative.V(AB) means voltage difference between A and B.
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
BS
The GCF is the absolute value of B
what is the absolute value of 5.24
x/a + x/b = 1Taking x as a common factor: x*(1/a + 1/b) = 1Adding the fractional parts x*(b/ab + a/ab) = 1or x*[(b + a)/ab] = 1Multiply both sides by (a+b)/abx = (a+b)/abAnother Approuch:-x/a+x/b = 1Multiply all terms by ab to eliminate the fractions:bx+ax = abFactorise:x(a+b) = abDivide both sides by (a+b):x = ab/(a+b)