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How can you find the Surface Area of a pyramid that is 8 feet tall 6 feet wide and has a depth of 7 feet?
Wiki User
∙ 14y ago
First, always start with the base. To find the base in a pyramid like that, and assuming that it forms a right triangle, you will need to use the Pythagorean Theorem on the right triangle to find the height of the rectangular base. Pythagorean theorem = a2 + b2 = c2.
You should get that the height of the base (hypotenuse of the triangle) is 10 feet. It is a multiple of a Pythagorean Triple, so you don't even need to use the Pythagorean theorem. Use A(rectangle) = bh to find the area of the base. So, B (area of base) = 70 ft2.
Now, find the perimeter of the base. You should get 34 ft.
Now you need to find the Lateral Area. LA (lateral area) = ph (perimeter of Base times the height of overall figure). You can figure out the height by splitting the side in half into two right triangles, and you can solve for the height (one of the sides of the newly formed right triangles) by using the Pythagorean theorem once again. LA = 34 X (6.26). LA = 212.84 ft2.
The formula for Surface Area is LA + B. SA (surface area) = 212.84 + 70 = 282.84 ft2.
Wiki User
∙ 14y ago
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