Anything times zero is zero.
If one is zero, then the product is always zero.(Think about it ... you take 279 zero times. How much do you have ?)
One or both of the numbers must be zero.
If zero is counted as a whole number, then the first three whole numbers are zero, one and two and the product of ANY series containing zero is ZERO. If, on the other hand, only non-zero numbers are considered, then the series is one, two and three and the product is six.
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If the product of 2 numbers is one, than those 2 numbers are recipricals
If one of the numbers is zero, zero point something or a negative number. Zero point something is a decimal starting with 0, eg. 0.4, 0.123
If one or both numbers are zero, then the answer is zero;if the two numbers have the same sign, then the answer is positive;if the two numbers have different signs, then the answer is negative.Incidentally, this is true of all real numbers, not just rationals.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
If all three numbers are positive then the product obviously has to be positive. If TWO of the three numbers are negative, then the product is also positive. But if exactly ONE of the three numbers is negative or if all THREE are negative, then the product must be negative. In general, a product of numbers is negative if an ODD NUMBER of the terms is negative.
2 is '2 more than five times 0'; their product is zero. This would make the answer (0, 2).
It is 0 because something times nothing is nothing It doesn't matter how many numbers you multiply or what they are, if one of the numbers you are multiplying is a zero, the product in the end becomes a zero. So, anything times anything times zero equals zero.