Using the positive square root (sqrt):
[sqrt(4)+sqrt(4)]*sqrt(4)+(4/4) = [2+2]*2 + (1) = 4*2 + 1 = 8 + 1 = 9.
You can get 9 with the sum 4 + 4 + (4/4) = 9
The answer is 9C4 = 9*8*7*6/(4*3*2*1) = 126 ways.
2,5,13,647,809
It is right under the giant r
How many 4s are in 36
_ (4/0.4)^sqrt4-4 =77 9 81 =77
9s - 9
999 + (9/9) = 1000
9+((9+9)/(9+9)) = 10
There are a few options for listing five prime numbers using the digits zero to nine only once:2, 3, 5, 7, 8649012, 5, 13, 647, 809
Five multiples of three that use each digit from 0 to 9 only once are: 12, 30, 45, 69, and 87.
9x9=81 9 9=18 9 to the power 0=1 81 18 1=100