999 + 999/999
It is: 8 times 125 = 1000
The sum 9 + 99 + 999 + 9999 + 99 999 + .... where the last number to be added consists of nine digits of 9 becomes: (10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ... where the last multiple of 10 has nine zeros. There are nine pairs of brackets altogether. Add the multiples of 10 first and then subtract 9: The digit 1 appears 9 times in the final answer.
5 times
About 111 times
A five digit number with 9 is 99999. A number which is 1000 times larger (not 1000 times as large) is 99999000.
999 + 999/999
One way could be: 999 +9/9 -9/9 +9/9 = 1000
9 x 1000 = 9000
8 x 1 + 5 x 1 over 100 + 9 x 1 over 1000 =[(8 x 1 + 5 x 1) ÷ 100] + [(9 x 1) ÷ 1000] =[(8 + 5 ) ÷ 100] + [(9) ÷ 1000] =[(13 ) ÷ 100] + [(9) ÷ 1000] =[13 ÷ 100] + [9 ÷ 1000] =[13 ÷ 100] + [9 ÷ 1000] =¹³/₁₀₀ + ⁹/₁₀₀₀ =¹³⁰/₁₀₀₀ + ⁹/₁₀₀₀ =¹³⁹/₁₀₀₀ or 0.139
It is 1000 times greater because 1000 times 0.09 = 90
It is: 8 times 125 = 1000
1000 times.
-405
The sum 9 + 99 + 999 + 9999 + 99 999 + .... where the last number to be added consists of nine digits of 9 becomes: (10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ... where the last multiple of 10 has nine zeros. There are nine pairs of brackets altogether. Add the multiples of 10 first and then subtract 9: The digit 1 appears 9 times in the final answer.
999 + 999/999 = 1000
5 times