-- Pick two points on the graph.
-- Find the difference in time between the two points.
-- Find the difference in displacement between the same two points.
-- (Difference in displacement) divided by (difference in time) is the average Speed .
You can't tell anything about velocity from the graph except its magnitude, because
the graph displays no information regarding the direction of motion.
Displacement is the area under the v-t graph.
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.
The answer depends on what variables the graph shows.
If the Object is falling at a constant velocity the shape of the graph would be linear. If the object is falling at a changing velocity (Accelerating) the shape of the graph would be exponential- "J' Shape.
It is the average velocity.
The Average Velocity on a position time graph or a velocity time graph.
To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting two points on the graph. Divide the change in displacement by the change in time. To obtain the instantaneous velocity, you need to find the slope of the tangent line at a specific point on the graph. Choose a point on the graph and draw a line tangent to the curve at that point. The slope of this tangent line will give you the instantaneous velocity at that specific point.
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
Displacement is the area under the v-t graph.
Yes it does. Velocity = Displacement / Time. On a graph of displacement vs time, the slope is the velocity. Steeper slope = higher velocity, flatter slope = lower velocity.
To get displacement from a displacement graph, just look at the Y- axis for the particular time (displacement versus time). For the displacement graph, the Y-axis is usually displacement.
A displacement vs. time graph of a body moving with uniform (constant) velocity will always be a line of which the slope will be the value of velocity. This is true because velocity is the derivative (or slope at any time t) of the displacement graph, and if the slope is always constant, then the displacement will change at a constant rate.
The total displacement divided by the time. The slope of the displacement vs. time graph.
The slope at each point of a displacement/time graph is the speed at that instant of time. (Not velocity.)
False. The slope of a velocity vs time graph is acceleration
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.