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The sum of the interior angles of a n-gon is (n-2)*180 degrees (n>2).

So the sum for a 50-gon would be 48*180 = 8640 degrees.

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15y ago

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(number of sides-2)*180 = total sum of interior angles

(50-2)*180 = 8640 degees

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14y ago
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Q: How could you find a sum in the angles of a 50 gon?
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