The sum of the interior angles of a n-gon is (n-2)*180 degrees (n>2).
So the sum for a 50-gon would be 48*180 = 8640 degrees.
find the sum of the measures of the interior angles of 13-gon.
the sum of the interior angles of a 35-gon.
9000
4,140
The sum of the interior angles add up to 3240 degrees.
The sum of interior angle ( Sum-of-interior-angles-n-gon) of n-gon is:If we have a ,Then
The formula is: (20-2)*180 = 3240 degrees which is the total sum of interior angles
5040
Yes
180x28 is the sum of the interior angles in a 30- gon
The exterior angles sum to 3600 , but the interior angles sum to 23400.
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.