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Let the dimensions be x and y:-
Perimeter: 2(x+y) = 24 => x+y = 12 => y = 12-x
Area: xy = 32 => x(12-x) = 32 => 12x-x2-32 = 0
Solving the above quadratic equation gives x = 4 and x = 8
Therfore the dimensions of the rectangle are 4 units by 8 units
Check: 2(4+8) = 24 units and 4*8 = 32 square units
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What is the area of a rectangle with a perimeter of 24 and a length of 8?
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What is the perimeter of the rectangle which is 32 square inches?
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