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Q: How do l work out the area of a the perimeter of a triangle?

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Add up the length of all sides

Area: Find some of the lengths, then cut the L in half and work it out from there. Perimeter: Add all the lengths together.

l + w + √(l2 + w2)

Rem to Find area and rectangle of a rectangle Input "Length?",l Input"Breadth?",b let area=l*b let perimeter=2*l+b ?area ?perimeter

as perimeter =8 so 4l=8 , so l=2. now area= [l][l]=(2)(2)=4

Perimeter l+l+w+w= 70ft Area LxW =300 sqft

I hope you want to know the Perimeter. Perimeter is the total length of the boundary of the region bounded by a shape. For a rectangle it is the sum of the 4 bounding sides, or 2*(L+B), where L is Length of the rectangle and B is Breadth of the rectangle. For a Triangle it is the sum of the 3 sides. If you consider an equilateral triangle. By property the 3 sides of an equilateral triangle are equal. Hence the Perimeter of an equilateral triangle is denoted as; 3*a, where a is the length of one of the sides of the triangle. It is possible that the perimeter of a rectangle is same as that of many different types of triangles. We can formulate a relationship for a special case where the perimeter of a rectangle is equal to the perimeter of an equilateral triangle; P(R) = P(ET), P(R) is perimeter of rectangle and P(EQ) is perimeter of Equilateral triangle. P(R)=2(L*B) = P(EQ) = 3*a; hence, a = (2/3)*(L*B) = P(R)/3. i.e., the sides of the Equilateral triangle are one thirds of the perimeter of the rectangle.

A square that measures 4 per side. Perimeter = L + L + L + L = 4L = 4*4 = 16 Area = L * L = 4*4 = 16 Although technically they won't be equal since perimeter has units of length, while area has units of squared length.

Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.

Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.

Suppose the lengths of the short sides of the triangle are L Then, by Pythagoras, the third side is sqrt(L2 + L2) = sqrt(2L2) = L*sqrt(2) So the perimeter is L+L+L*sqrt(2) = L*[2+sqrt(2)] Also, if the length of the two short sides is L, the area, A, is 0.5*L*L that is A = 0.5*L2 or L = sqrt(2*A) Combining the two equations, given A, he perimeter is sqrt(2*A)*[2+sqrt(2)] =sqrt(A)*[2*sqrt(2)+2] or 2*sqrt(A)*[1+sqrt(2)] Hope that is correct and helps.

Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.

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