Assuming you mean four different numbers, 0.123
You do not need a function to determine the lowest common factor of two numbers. The lowest factor of any one number is 1. The lowest common factor of any two numbers is therefore 1 as well.
in whole numbers (without using fractions) there is no answer; 95 over 27 is the lowest term available
It depends on what numbers you are using so thats the first question.
The set of natural numbers (counting numbers) {1,2,3,4....} corresponds to the positive integers. Note that the number 0 is neither positive nor negative. So anytime you want to count something you use natural numbers, which means you are also using positive integers.
24680
123 123 123
36 - 18
If you had an array int numbers[10]; you would do it like this: CODE: int lowestnumber = numbers[0]; for(int i = 0; i < 10; i++){ if(numbers[i] < lowestnumber) lowestnumber = numbers[i]; } END CODE I think this should work, and in the end the variable lowestnumber will hold the lowest value in the ten. Hope this helps.
Any relationship, including "no relationship".
This is easiest to understand using small numbers and the X,Y grid using the negative numbers to the left of 0 and positive to the right. By following the normal rules of multiplication, multiplying a negative number by a positive number moves the product further to the left from zero.
just create a mathematical equation using 1964 such as 1x1964 2x1964 3x1964 4x1964 or 1964/1 1964/2 etc
Negative numbers do not have "real number" square roots.However, they will have two roots (when using imaginary numbers) as do other numbers, where a root including i(square root of -1) is positive or negative.