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Algebraically:

((a+b) / 2) / ((a+b) / (2ab)) = 2ab(a + b) / 2(a + b) = (2a2b + 2ab2) / (2a + 2b) = ab

As an example, let a = 2 and b = 3 then:

i) (a + b) / 2 = (2 + 3) / 2 = 5/2

ii) (a + b) / (2 * a * b) = (2 + 3) / (2 * 2 * 3) = 5 / 12

Therefore i) is ab times larger than ii). (for these specific example numbers it will be 6 times larger)

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