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How do you determine the x-intercept given an equation?
Put f(x) = 0 and solve for x.
If 3 8 6 x then tha value of x?
Not enough information has been given to determine the value of x
Are the function F of x equals -2over 3 plus 1 and determine the slope explain?
The function that is given has a constant value and therefore, its slope is 0.
What is The test to determine if a graph is a function is?
A graph is represents a function if for every value x, there is at most one value of y = f(x).
How can you determine the rate of change and initial value of a relation from its equation?
If the equation is of the form y = f(x) where f is some function of the variable x, then The initial value is found by evaluation f(0): that is, the value of f(x) when x = 0. The rate of change is the derivative of f(x) with respect to x, written as f'(x). That is the limit (if it exists), as dx tends to 0, of [f(x+dx) - f(x)]/dx. In the simple case, where f(x) is a linear equation of the form y = mx + c, then f(0) = c and f'(x) = m
How do you determine the x-intercept given an equation?
Put f(x) = 0 and solve for x.
If 3 8 6 x then tha value of x?
Not enough information has been given to determine the value of x
Are the function F of x equals -2over 3 plus 1 and determine the slope explain?
The function that is given has a constant value and therefore, its slope is 0.
If the area of the trapezoid below is 75 square units what is the value of x?
Not enough information has been given to determine the value of x
What is The test to determine if a graph is a function is?
A graph is represents a function if for every value x, there is at most one value of y = f(x).
How can you determine the rate of change and initial value of a relation from its equation?
If the equation is of the form y = f(x) where f is some function of the variable x, then The initial value is found by evaluation f(0): that is, the value of f(x) when x = 0. The rate of change is the derivative of f(x) with respect to x, written as f'(x). That is the limit (if it exists), as dx tends to 0, of [f(x+dx) - f(x)]/dx. In the simple case, where f(x) is a linear equation of the form y = mx + c, then f(0) = c and f'(x) = m
How do you find the x value of an equation if you are only given the value of y using function notation?
You use the inverse function (if one exists).So, if y = f(x) then x = f-1(y)
What is the correct procedure for epsilon-delta proofs in Calculus?
A function f(x), of a variable x, is said to have a limiting value of f(xo) as x approaches x0 if, given any value of epsilon, however small, it is possible to find a value delta such that |f(x) - f(x0)| < epsilon for all x such that |x - x0| < delta.The second inequality can be one-sided.
How do you determine if a function is even?
A function f(x) is Even, if f(x) = f(-x) Odd, if f(x) = -f(-x)
How can you write a function that represents all possible antiderivatives of a given function?
Given a function f(x) find any anti-derivative, F(x). The set of all possible derivatives is obtained by adding a term not involving x which can take any value. So F(x) + C is a general derivative, where C can take any value.
What is the value of f(8) for the function f(x) 8x plus 5?
Given f(x) = 8x + 5 So f(8) = 8 * 8 - 5 = 64 - 5 = 59
What does the expression approaching a given value mean in mathematics?
If you are talking about a function in a variable (lets say f(x)=1/x) then it probably means that as x gets bigger and bigger, the function f(x) starts to settle around a certain number, ie: f(x) is the same for two really big numbers that are different. With f(x)=1/x we have f(1000000)=1/1000000=0.000001 and f(2000000)=1/2000000=0.0000005 Which are both VERY, VERY close to 0. SO in this example the expression (f(x)=1/x) is approaching a given value of 0.
