You use the inverse function (if one exists).
So, if y = f(x) then x = f-1(y)
True
function composition
x = 9/2 or x = -2 Solved by using the quadratic equation formula.
Not sure what you mean by "zero element". If an expression is equal to zero, and you can factor it, then at least one of the factors must be zero; this is often useful to solve an equation.
The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
The potential can be calculated from the wave function using the Schrödinger equation, where the potential energy operator acts on the wave function. This involves solving the time-independent Schrödinger equation to find the potential energy function that corresponds to the given wave function. The potential can be obtained by isolating the potential energy term on one side of the equation.
To reduce the expression of a mathematical equation using Mathematica, you can use the Simplify function. Simply input the equation into Mathematica and apply the Simplify function to simplify and reduce the expression.
let's take an arbitrary equation, or maybe two or three so you can see how to do it. y=2x+6 t=z^2+3z w=r^4+pi Ok, the first equation, you pick the x and put it in the equation and multiply it by 2 then add 6. If you do all this you get y. So y is really a function of x or function of x is written f(x) is the way we say this So to write the equation in function notation we write f(x)=2x+6 Same thing for the second equation z is what we put in. It is the independent variable. So t is just a function of z we write f(z)=z^2+3z Last equation is the same f(r)=r^4+pi
The solution to the Heat equation using Fourier transform is given by the convolution of the initial condition with the fundamental solution of the heat equation, which is the Gaussian function. The Fourier transform helps in solving the heat equation by transforming the problem from the spatial domain to the frequency domain, simplifying the calculations.
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
I guess you mean an equation written in function notation, for example: f(x) = 3x + 2 For the purposes of doing math, it may help to think of this as an alternative way of writing, for example (using the function above): y = 3x + 2 It isn't clear from the question what you want to "solve", but if you write the equation this way, it might become a bit less confusing.
h(w)=100/w
If it is a linear function, it is quite easy to solve the equation explicitly, using standard methods of equation-solving. For example, if you have "y" as a function of "x", you would have to solve the variable for "x".
define function formally and using f(x) notation
Verticle line test man. If it intersects two points it is its not a function. if it hits one point it is a function. and im currently looking up to see how it is a equation...
MATLAB can be used to find the roots of a given equation by using the built-in functions like "roots" or "fzero". These functions can solve equations numerically and provide the values of the roots. By inputting the equation into MATLAB and using these functions, the roots can be easily calculated and displayed.
If you mean: x-2y = 8 then it is y = 0.5x-4.