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In dividing (18x⁹ -12x⁷ -8x⁶ -2x³) ÷ -2x² you could do long division, but as the divisor contains a single term like a normal fraction each term of the dividend can be divided by the divisor and summed together:

(18x⁹ -12x⁷ -8x⁶ -2x³) ÷ -2x² = (18x⁹ -12x⁷ -8x⁶ -2x³)/(-2x²)

= 18x⁹/(-2x²) + -12x⁷/(-2x²) + -8x⁶/(-2x²) + -2x³/(-2x²)

= (18 ÷ -2)(x⁹ ÷ x²) + (-12 ÷ -2)(x⁷ ÷ x²) + (-8 ÷ -2)(x⁶ ÷ x²) + (-2 ÷ -2)(x³ ÷ x²)

= -9x⁹⁻² + 6x⁷⁻² + 4x⁶⁻² + 1x³⁻²

= -9x⁷ + 6x⁵ + 4x⁴ + x

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Q: How do you divide the following expression. Assume that the denominator is nonzero. 18x9 -12x7 -8x6 -2x3 all divided by -2x2?
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