It depends on the operation - for multiplication, the ammount of significant figures is the same as the multiple that has the least. Same for division. For subtraction and addition, the significant figures are decided by the least ammount of spaces past the decimal in the answer. For example, 30.7+2.111111111 would be 30.8
The question is based on a fallacy. Volumes can be reported in any number of significant figures.
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
No. Stating more significant figures in a quantity doesn't guarantee that the figures are true.
You make you're calculations using has many (or more) significant figures as requested without any further considerations until you get to the final result... You reduce the final results significant figures to the requested one or add zeros at the end to match it if it is an exact result
The simple rule is: no more significant figures than the least accurate of the values in the computation. For multiplication and division, the result should have as many significant figures as the measured number with the smallest number of significant figures. For addition and subtraction, the result should have as many decimal places as the measured number with the smallest number of decimal places. (Rounding off can be tricky, but that would be another thread)
That depends on the context in which it is found, or the calculation(s) involved. It should have no more significant figures than the value with the least number of sig. figs.
The greater the number of significant figures, the greater the precision. Each significant figure increases the precision by a factor of ten. For example pi = 3.14 is accurate to 3 significant figures, while pi = 3.14159 with 6 significant figures is a more accurate representation.
You just did. Here's two more: The number 303 has three significant figures. George Washington and Thomas Jefferson were significant figures in the American Revolution.
Three, so the answer would be 3.96. Always use the number with the smallest amount of significant figures to determine the amount of significant figures will be in the solution.
It varies. Volume may be reported with more or less significant figures. However, in general the result should not have more significant figures than the underlying data - otherwise, it would look more accurate than it really is.
Significant figures are used to receive a more accurate number. To obtain the number you you multiply or divide the quantities, leave as many significant figures in the answer as there are in the quantity with the least number or significant figures. If adding or subtracting quantities, leave the same number of decimal places in the answer as there are in the quantity with the least number of decimal places
The question is based on a fallacy. Volumes can be reported in any number of significant figures.
A significant figure is basically counting how many digits there are: In this case this number is to FOUR significant figures because there are FOUR digits. Here's some more examples: When you have zero's in front of the number, these do not count as digits: so, if you had 0.0034, you only count the 3 and 4 as digits so this would be to TWO significant figures. However, if you have 0.003404, you must count the zero in between the two four's because this is part of the number - there are FOUR significant figures here.
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
The answer depends on what operations were used. There should normally not be more significant figures in the answer than in any of the numbers used in the calculation.
Significant figures are important because they indicate the degree of accuracy - the minimum amount by which a quantity is distinguished to be different from a similar amount.The more significant figures the more accurate the data will be.
It's more easier to understand the measurements that is given. Instead of those crazy, hard- to- look- at equation, the significant figures make it more practical and easier to understand.