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(7x + 4)(x - 1)
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∙ 8y ago
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How do you factor 7x2-3x plus 4?
It can't be factored because its discriminant is less than zero
How do you factor 7x squared 32x 16?
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16
Factor the polynomial 7x2 plus 68xy - 20y2?
7x2 + 68xy - 20y2
How do you factor the polynomial 9x2 plus 24x plus 16 with each factor as a polynomial in descending order?
(3x + 4)(3x + 4)
How do you factor 7x2 49?
7(x2 + 7)
How do you factor 7x2-3x plus 4?
It can't be factored because its discriminant is less than zero
How do you factor x3 plus 7x2 plus 18x plus 24?
I know the answer is x(x^2+3x+6) + 4(x^2+3x+6) which factors to (x+4)(x^2+3x+6) but I don't know the rule behind this. Could someone explain it to me?
What is the greatest common factor for 35x6 and 7x2?
7x2
How do you factor 7x squared 32x 16?
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16
How do you factor 7x2-31x-20?
(7x + 4)(x - 5)
What type of expression is 7x2 plus 3x?
Algebraic expression.
What is the factor of 9x squared -16?
(3x-4)(3x+4)
How do you factor 9x2-0x-16?
(3x + 4)(3x - 4)
Factor the polynomial 7x2 plus 68xy - 20y2?
7x2 + 68xy - 20y2
How do you factor 28x3-7x2 plus 36x-9?
(7x2 + 9)(4x - 1)
What is the resolve form of 9x2 - 9x - 4 in factor?
3x + 1)(3x - 4)
Factor x4 - 3x3 - 7x2 plus 27x -18?
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.
