It can't be factored because its discriminant is less than zero
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16
7x2 + 68xy - 20y2
(3x + 4)(3x + 4)
7(x2 + 7)
It can't be factored because its discriminant is less than zero
I know the answer is x(x^2+3x+6) + 4(x^2+3x+6) which factors to (x+4)(x^2+3x+6) but I don't know the rule behind this. Could someone explain it to me?
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16
7x2
(7x + 4)(x - 5)
Algebraic expression.
(3x-4)(3x+4)
(3x + 4)(3x - 4)
7x2 + 68xy - 20y2
(7x2 + 9)(4x - 1)
3x + 1)(3x - 4)
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.