It can't be factored because its discriminant is less than zero
(2x+4)(x+1)
(3x + 4)(3x + 4)
4(3y+4)
ab + 4 + a + 4b factors to (a + 4)(b + 1)
It is: 4(x+3)
a + b + 4 is in its simplest form.
Not factorable
6x+4 factor: 2(3x+2)
(2x + 1)(x + 4)
a2 - 4a + 4
(2x+4)(x+1)
(3x + 4)(3x + 4)
(x+1)(x+4)
4(x + 1)(x + 1)
(x-1)(x+4)
That's 44v + 4 which factors to 4(11v + 1)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)