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Q: What is the greatest common factor for 35x6 and 7x2?

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(7x + 4)(x - 5)

The common factors of 14 and 49 are 1 and 7.1x49=49 1x14=147x7=49 7x2=14 1 and 7

if the x in "7x2" is variable x, then 7x(2)-5x=0 14x-5x=0 9x=0 x=0 if the x in "7x2" is a symbol for multiplication, then 7(2)-5x=0 14-5x=0 -5x= -14 5x=14 x= 14/5 x= 2 4/5 or, to factor it out... x(14-5)=0 x(9)=0 9x=0

The exponent tells how many times the base is used as a factor. 23 = 2 x 2 x 2

Factor 7x2 - 9x - 10 = 0.7 * -10 = -7070 = 2 * 35 = 2 * 5 * 7Factors of 70: 1,2,5,7,10,14,35,701 x 70 = 702 x 35 = 705 x 14 = 707 x 10 = 70The sum should be negative, so the larger number in the sum must be negative.product of -70 (sum of -9) :1 + (-70) = -692 + (-35) = -335 + (-14) = -97 + (-10) = -3The sums match up, so now we have the factors.(x+5)(x+(-14)) = 0(x+5)(x-14) = 0However, the x2 must have a 7 in front of it, so divide the 14 by 7.(7x+5)(x-2) = 0And, if you have extra time, you can foil it back out to make sure you did it correctly.7x2 - 14x + 5x -10 = 07x2 - 9x - 10 = 0This confirms that the factorization is correct.Finally, if you want to solve for x, just set each term equal to zero.7x+5 = 0 or x-2 = 07x = -5 or x = 2x = -5/7 or 2

Related questions

You can take 7x2 out of both of those, leaving 5x4 and 1.

The GCF is x2

7x2 + 68xy - 20y2

(7x2 + 9)(4x - 1)

Yes, they have the common factor of 7. 14 is 7x2, 35 is 7x5

7(x2 + 7)

I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).

1. 3x2+12= 3(x2+4) 2. 7x2+35x= 7x(x+5)

(x - 3)(7x + 2)

(7x + 4)(x - 1)

(7x + 6)(x - 2)

(7x + 4)(x - 5)

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