Study guides

☆☆

Q: How do you factor 8x2 plus 18x plus 7?

Write your answer...

Submit

Still have questions?

Related questions

(-3x - 1)(3x - 7)

(2x+5)(4x-7)

8x2+6x-35 = (4x-7)(2x+5) when factored

6x5(x2 - 6x + 3)

8x2+6x-35 = (2x+5)(4x-7) when factored

x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}

-5 + 12x = 18x + 7Subtract 7 from each side:-12 + 12x = 18xSubtract 12x from each side:-12 = 6xDivide each side by 6:-2 = x

8x2 + 15x + 7 = 0 factors to(8x + 7) (x + 1) = 0Therefore the 2 linear equations are:1. 8x + 7 = 0Thus 8x = -7x = -0.875and2. x + 1 = 0Thus x = -1

Assuming that's -35, that factors to (2x + 5)(4x - 7)

8x

That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-1 plus or minus one third itimes the square root of 7) divided by 4.x = -0.25 + 0.22047927592204922ix = -0.25 - 0.22047927592204922iwhere i is the square root of negative one.

Assuming the missing signs are pluses, that factors to 3(4x^2 + 6x + 7)

People also asked