(2x + 1)(4x + 7)
(-3x - 1)(3x - 7)
8x2+6x-35 = (4x-7)(2x+5) when factored
6x5(x2 - 6x + 3)
8x2+6x-35 = (2x+5)(4x-7) when factored
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
-5 + 12x = 18x + 7Subtract 7 from each side:-12 + 12x = 18xSubtract 12x from each side:-12 = 6xDivide each side by 6:-2 = x
8x2 + 15x + 7 = 0 factors to(8x + 7) (x + 1) = 0Therefore the 2 linear equations are:1. 8x + 7 = 0Thus 8x = -7x = -0.875and2. x + 1 = 0Thus x = -1
-3(x + 2)(x + 4)
If you mean (11x -8)+7(x -1) then it is 18x -15 when simplified
Type your answer here... (2x + 5)(4x - 7)
The center of the circle is at (9, 7) on the Cartesian plane
8x