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The center of the circle is at (9, 7) on the Cartesian plane

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What is a chord passing through the center of a circle?

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What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?

Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.


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Find the center and radius of the circle with this equation x2 plus y2 plus x equals 0?

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How do you find the radius of the circle when you know the center and a point on the circle?

measure it