(3 - 4y)(3 + 4y)
(4y - 1)(16y2 + 4y + 1)
(x + 2y)(3x + 8y)
2y(2y - 1)(2y - 3)
2y(2y - 1)(2y - 3)
No.
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
The difference of cubes has a formula. (4x - y)(16x2 + 4xy + y2)
For a polynomial a2 - b2 = (a + b)(a - b).So for x2 - 16y2 ---> a = x, and b = 4y: (x + 4y)(x - 4y)
(4y)2 = 16y2
64y3 - 216x3 factors to -8(3x - 2y)(9x2 + 6xy + 4y2) 49x2 - 16y2 factors to (7x - 4y)(7x + 4y)
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4