16y^2(8y)=0?
Factor out an 8y to give you 8y(2y(2))=0
Use order of operations to give you 8y(4y)=0
Distribute to give you 32y=0
and ultimately the answer will be 0
If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors:
16y2 ± 8y = 0
⇒ 8y(2y ± 1) = 0
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
x = 2, y = 84x + 8y= 4(2) + 8(8)= 8 + 64= 72
Not sure which you mean, take your pick: (8y)3+27=(8y+3)((8y)2-3*(8y)+9)=(8y+3)(64y2-24y+9); or 8y3+27=(2y+3)(4y2-6y+9)
8y + 7y = 15ySo [ 8y + 9 + 7y ] = 15y + 9If you want to get fancy and factor that expression, it's 3(5y + 3) .
20
2(8y + 1)
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
It cannot be done using real numbers. However, it can be done using complex numbers: 16y² + 4y + 1 = ¼(8y + (1 + i√3))(8y + (1 - i√3))
8y squared + 52y - 180
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
0
7
The 4y-4y cancels out and you should be left with 16. But it's not solve-able in that sense because there is no equals sign. Simplified, though, I believe it comes to 16.
LCM(10y2 , 8y) = 40y2
-16
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
The only thing you can do to this is factor it... (4x + 8y)(4x - 8y)