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16y^2(8y)=0?

Factor out an 8y to give you 8y(2y(2))=0

Use order of operations to give you 8y(4y)=0

Distribute to give you 32y=0

and ultimately the answer will be 0

If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors:

16y2 ± 8y = 0

⇒ 8y(2y ± 1) = 0

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12y ago

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More answers

16y2-8y=0

8y(2y-1)=0

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14y ago
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Q: How do you factor 16y squared - 8y equals 0?
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