9y^-30y^ + 24y^3 = 2y^3(3y - 4)(y - 2)
The GCF is 2.
The GCF is 3y2
The GCF is 8y^3.
Since 3y2 can evenly divide 24y3, 3y2 must be the greatest common factor, since the greatest common factor cannot be larger than the smaller of the two numbers. But, we can also look at a factorization of both numbers. We can tell that 3y2 = 3 x y2. We can tell that 24y3 = 3 x 8 x y3 = 3 x 23 x y2 x y. These numbers have in common 3 and y2, so 3y2 is the greatest common factor.
5m
The other factor is 1.
(a + 2b)(a + 2b)
factor the trinomial 16x^2+24x+9
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
That does not factor neatly.
You can't factor it
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).