Q: How do you factor T2 plus 4T?

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(t + 7)(t - 1)

4t + 13t + 2 = 17t + 2

9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer

If 4t + 5 = 37, then t = 8.

4t +7

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(u + 4)(6u - t)

(t - 7)(t - 11)

(t + 7)(t - 1)

4t + 13t + 2 = 17t + 2

4(t + 3)(t2 - 3t + 9)

9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer

If 4t + 5 = 37, then t = 8.

Subtract 21 from both sides. If that's + 4t, the answer is (t - 3)(t + 7) and t = 3, -7 If that's - 4t, the answer is (t + 3)(t - 7) and t = -3, 7

4t +7

There are no solutions because the discriminant of this quadratic equation is less than zero

3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)

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