(t + 7)(t - 1)
Chat with our AI personalities
T(t + 4)
-13
(4x - t2)= [(2√x)2 - t2] (This is now the difference of squares)= (2√x - t)(2√x + t)
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
If you mean t^2 +11t +10 then it is (t+10)(t+1) when factorized