4(t + 3)(t2 - 3t + 9)
t2 - 59t + 54 - 82t2 + 60t = - 81t2 + t + 54
12t(t2-4) 12t(t-2)(t+2)
assuming that you meant (360t + 10t3- 120t2 )then you can factor both 10 and T out of all three because it's a common factor10t(36+t2-12t), this is because if I was to times everything inside the bracket by 10t then I would have the original equation we started with.This can also be factored even more.(10t)(t-6)(t-6) because (t-6) X (t-6) is the same as (t2-12t+36)Thus the final factored form is (10t)(t-6)(t-6)
Avogardo's Law
T(t + 4)
(t + 7)(t - 1)
4(t + 3)(t2 - 3t + 9)
t2 - 59t + 54 - 82t2 + 60t = - 81t2 + t + 54
-13
(t-8)(t + 3)
(4x - t2)= [(2√x)2 - t2] (This is now the difference of squares)= (2√x - t)(2√x + t)
If you mean t(t+7) = 4(3+2t), then it is factored. If you meant solve for 't', then the solution is t = t2 - 12.
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
(t - 15)(t + 3)
12t(t2-4) 12t(t-2)(t+2)
If you mean t^2 +11t +10 then it is (t+10)(t+1) when factorized