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Q: How do you factor the expression 9 minus i squared?

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x2-81 = (x-9)(x+9)

(x - 3)(x + 3)

(a + 3)(a - 3)

The discriminant of this quadratic expression is less than zero therefore it cannot be factored.

(9 - 5u)(9 + 5u)

(x + 2)(x - 9)

(7x + 8)(7x - 9)

9(2x - 1)(2x + 1)

(x - 1)(2x - 9)

Since 3 squared is 9 and 9 - 9 equals 0, that's going to be tough to factor.3x2 - 9 factors to 3(x2 - 3)

(2y + 3)(2y - 3)

(10x-3(10x+3)

1x^2-6x+91X9 IS 9What multiplies to get 9 and adds to get -6? -3x-3So, (x-3)(x-3)

y2-y-72 is an algebraic expression that can be factored as: (y+8)(y-9)

x2 - 6x - 27 = (x-9)(x+3)

(8x - 3)(8x + 3)

(2x - 9)(2x - 9) or (2x - 9)2

It is a quadratic expression which can be factored to (7b+9)(8b-7) after dividing all terms by 2

It is: (g-5)(g-9)

(4x - 3)(2x + 3)

(x - 6)(x + 9)

x2-5x-36 = (x-9)(x+4) when factored

(2x - 9)(2x +9)

9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)

(x^2 - 4)(x^2 + 9) set to zero to see roots ( watch out for the surprise! )