x³ - x² + x - 3 (x² + 1)(x - 1) - 2
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
The discriminant of this quadratic expression is less than zero therefore it cannot be factored.
You don't! There are no common factors.
(3y - 5)(y + 5)
(x - 2)(2x - 3)
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
x2 - 9x + 20 = (x - 4)( x - 5)
It is a quadratic expression
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
The discriminant of this quadratic expression is less than zero therefore it cannot be factored.
This expression factors as x -1 quantity squared.
There are no rational factors.
There is no rational factorisation.
You don't! There are no common factors.
(a - 2)(a^2 + 6)