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x³ - x² + x - 3 (x² + 1)(x - 1) - 2

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Q: How do you factor the expression x cubed minus x squared plus x minus 3?

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x(x + 3)(x - 4)

(2x3 - x2) = x2 (2x - 1)

To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.

(x - 5)(x^2 + 1)

(x - 5)(x^2 + 5x + 25)

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(3 - i)(3 + i)

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x(x + 3)(x - 4)

Without that other number, all you've got is zero.

Factor out the GCF and get X(X2-X+1).

To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.

(2x3 - x2) = x2 (2x - 1)

(x + 6)(x - 6)

(x - 2)(x^2 + x + 3)

(x + 2)(3x - 1)(3x + 1)

(x - 5)(x^2 + 1)

xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1