To factor out the expression:
x2y-y3
First factor out one "y":
y(x2-y2)
The expression x2-y2 is a difference of squares, which factors as well:
(y)(x-y)(x+y)
This is the simplest factoring of the original expression.
x(x + 3)(x - 4)
x cubed minus 216
(2x3 - x2) = x2 (2x - 1)
(x - 5)(x^2 + 1)
x(x - 19)(x - 1)
(a - 2)(a^2 + 6)
x(x + 3)(x - 4)
x cubed minus 216
Factor out the GCF and get X(X2-X+1).
(2x3 - x2) = x2 (2x - 1)
(x - 2)(x^2 + x + 3)
(x + 2)(3x - 1)(3x + 1)
(x - 5)(x^2 + 1)
x(x - 19)(x - 1)
9 minus 8
n(2n - 1)(2n + 7)
(x2 + 1)(x2 - 2)