x(x^2 + 2)
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
It could be x3 + 2x + 0It could be x3 + 2x + 0It could be x3 + 2x + 0It could be x3 + 2x + 0
(x - 1)(x2 + x - 1)
(2x - 1)(x + 2)(x^2 - 2x + 4)
(x + 2)(x^2 + 2x + 3)
(x + 5)(x^2 + 2x + 2)
I'm going to assume x3 is x3 and then you have 2x(1+6x2). Another reading is that 12x3 is 36, in which case you get 2(x+18).
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
7 x3 + 2 x = x (7 x2 + 2)
2x3 + 16 = 2(x3 + 8) = 2(x3 + 23) = 2(x + 2)(x2 - 2x + 22) = 2(x + 2)(x2 - 2x + 4)
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
That depends on whether or not 2x is a plus or a minus