(x-2)(x+1)(x+5)
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
7 x3 + 2 x = x (7 x2 + 2)
4X2+X3+3X+7Y+2X3 can only be simplified to 3X3+4X2+3X+7Y, because X3 and 2X3 are the only like terms.
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
(x + 1)(x - 2)(x + 5)
(x-2)(x+1)(x+5)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
(x + 7)(x2 - 7x + 49)
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
(x - 2)(x + 4)(x - 6)
5x is a common factor of all terms:- 5x(x3+4x2+9)
[ x3 - 4x2 + 7x ] / (x) = x2 - 4x + 7
X3 - 4X2 - 45XX(X2 - 4X - 45)=============X is only common factor here.
7 x3 + 2 x = x (7 x2 + 2)
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)